try_sum aggregate function (Databricks SQL)

Returns the sum calculated from values of a group, or NULL if there is an overflow.

Syntax

try_sum ( [ALL | DISTINCT] expr ) [FILTER ( WHERE cond ) ]

Arguments

  • expr: An expression that evaluates to a numeric or interval.

  • cond: An optional boolean expression filtering the rows used for aggregation.

Returns

If expr is an integral number type, a BIGINT.

If expr is DECIMAL(p, s) the result is DECIMAL(p + min(10, 31-p), s).

If expr is an interval the result type matches expr.

Otherwise, a DOUBLE.

If DISTINCT is specified only unique values are summed up.

If the result overflows the result type Databricks SQL returns NULL. To return an error instead use sum.

Examples

> SELECT try_sum(col) FROM VALUES (5), (10), (15) AS tab(col);
 30

> SELECT try_sum(col) FILTER(WHERE col <15)
    FROM VALUES (5), (10), (15) AS tab(col);
 15

> SELECT try_sum(DISTINCT col) FROM VALUES (5), (10), (10), (15) AS tab(col);
 30

> SELECT try_sum(col) FROM VALUES (NULL), (10), (15) AS tab(col);
 25

> SELECT try_sum(col) FROM VALUES (NULL), (NULL) AS tab(col);
 NULL

-- try_sum overflows a BIGINT
> SELECT try_sum(c1) FROM VALUES(5E18::BIGINT), (5E18::BIGINT) AS tab(c1);
 NULL

-- In ANSI mode sum returns an error if it overflows BIGINT
> SELECT sum(c1) FROM VALUES(5E18::BIGINT), (5E18::BIGINT) AS tab(c1);
 ERROR

-- try_sum overflows an INTERVAL
> SELECT try_sum(c1) FROM VALUES(INTERVAL '100000000' YEARS), (INTERVAL '100000000' YEARS) AS tab(c1);
  NULL

-- sum returns an error on INTERVAL overflow
> SELECT sum(c1) FROM VALUES(INTERVAL '100000000' YEARS), (INTERVAL '100000000' YEARS) AS tab(c1);
 Error: ARITHMETIC_OVERFLOW